Casein Tryptone 是一种混合物或盐类化合物,具有复杂的多环结构。其化学身份由结构数据支持,表明含有多个酯基和醚基,但由于其柔韧性、未定义的立体中心以及混合物或盐的性质,构象生成被禁止。
内容范围: 本页信息面向化学品识别与工业供应、研发、生产场景,不构成疗效宣称、医疗建议或药品使用指导。
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CAS 91079-46-8
Casein Tryptone
微生物培养基组分
3-hydroxynaphthalene-1-carbaldehyde
研究化合物
1-Fluoro-4-(trans-4-(2-(trans-4-propylcyclohexyl)ethyl)cyclohexyl)benzene
科研用化学化合物
8-aminoquinoline-2-carboxylic Acid
研究试剂和药物中间体
4-Bromo-3-chloro-1,1'-biphenyl
化学中间体
3,12-bis[5-(2,2-dimethyl-4,6-dioxo-1,3-dioxan-5-ylidene)penta-1,3-dienyl]-4,13-dioxo-1,5,10,14-tetraoxadispiro[5.2.59.26]hexadeca-2,11-diene-2,11-diolate;3,12-bis[5-(2,4-dioxo-1,5-dioxaspiro[5.5]undecan-3-ylidene)penta-1,3-dienyl]-4,13-dioxo-1,5,10,14-tetraoxadispiro[5.2.59.26]hexadeca-2,11-diene-2,11-diolate;3-[5-[12-[5-(8,11-dimethyl-2-oxido-4-oxo-1,5-dioxaspiro[5.5]undec-2-en-3-yl)penta-2,4-dienylidene]-2,4,11,13-tetraoxo-1,5,10,14-tetraoxadispiro[5.2.59.26]hexadecan-3-ylidene]penta-1,3-dienyl]-8,11-dimethyl-4-oxo-1,5-dioxaspiro[5.5]undec-2-en-2-olate;2-ethyl-5-[5-[12-[5-(2-ethyl-2-methyl-4-oxido-6-oxo-1,3-dioxin-5-yl)penta-2,4-dienylidene]-2,4,11,13-tetraoxo-1,5,10,14-tetraoxadispiro[5.2.59.26]hexadecan-3-ylidene]penta-1,3-dienyl]-2-methyl-6-oxo-1,3-dioxin-4-olate;tetrakis(4-[4-[1-(4-hydroxy-3-phenylphenyl)pyridin-1-ium-4-yl]pyridin-1-ium-1-yl]-2-phenylphenol)
DENDBKLJAQIVGF-UHFFFAOYSA-N
CCC1(OC(=C(C(=O)O1)C=CC=CC=C2C(=O)OC3(CCC4(CC3)OC(=O)C(=CC=CC=CC5=C(OC(OC5=O)(C)CC)[O-])C(=O)O4)OC2=O)[O-])C.CC1CCC(C2(C1)OC(=C(C(=O)O2)C=CC=CC=C3C(=O)OC4(CCC5(CC4)OC(=O)C(=CC=CC=CC6=C(OC7(CC(CCC7C)C)OC6=O)[O-])C(=O)O5)OC3=O)[O-])C.CC1(OC(=O)C(=CC=CC=CC2=C(OC3(CCC4(CC3)OC(=C(C(=O)O4)C=CC=CC=C5C(=O)OC(OC5=O)(C)C)[O-])OC2=O)[O-])C(=O)O1)C.C1CCC2(CC1)OC(=O)C(=CC=CC=CC3=C(OC4(CCC5(CC4)OC(=C(C(=O)O5)C=CC=CC=C6C(=O)OC7(CCCCC7)OC6=O)[O-])OC3=O)[O-])C(=O)O2.C1=CC=C(C=C1)C2=C(C=CC(=C2)[N+]3=CC=C(C=C3)C4=CC=[N+](C=C4)C5=CC(=C(C=C5)O)C6=CC=CC=C6)O.C1=CC=C(C=C1)C2=C(C=CC(=C2)[N+]3=CC=C(C=C3)C4=CC=[N+](C=C4)C5=CC(=C(C=C5)O)C6=CC=CC=C6)O.C1=CC=C(C=C1)C2=C(C=CC(=C2)[N+]3=CC=C(C=C3)C4=CC=[N+](C=C4)C5=CC(=C(C=C5)O)C6=CC=CC=C6)O.C1=CC=C(C=C1)C2=C(C=CC(=C2)[N+]3=CC=C(C=C3)C4=CC=[N+](C=C4)C5=CC(=C(C=C5)O)C6=CC=CC=C6)O